Hi Angshu,Very interesting experiment. Is the B is in hexameric form in solution by itself or it requires A for hexamer formation? Thanks,Reza Md Rezaul Karim PhD candidate PhD Program in Integrated Biomedical Sciences Dept. of Molecular Medicine, Morsani College of Medicine, USF,Tampa Schonbrunn lab, Moffitt Cancer Center, Tampa Email: rez...@health.usf.edu, md.ka...@moffitt.org Phone: (813) 745 4673 ext. 5462 On Fri, Feb 21, 2020 at 9:59 AM, DUMAS Philippe (IGBMC)<p.du...@ibmc-cnrs.unistra.fr> wrote: Dear AngshuThe answer to your question requires to define precisely the term of "stoichiometry".*If you consider the hexamer as "the molecule B", then the expected stoichiometric ratio is 1/1 (one molecule A should bind to 1 hexamer B).*But if you consider the monomer of B as "the molecule" in the cell, then the expected stoichiometric ratio is 1/6 (one molecule of A should bind to 6 monomers of the hexamer B). Accordingly, you have to define the concentration in the cell as follows: if you consider the hexamer as "the molecule B" and, let's suppose you have [B] = 10 µM of hexamer, then [B] = 60 µM if you consider the monomer of B as "the molecule".I hope I answered your question.Philippe Dumas De: "Angshu Dutta" <angshu.cryst...@gmail.com> À: "CCP4BB" <CCP4BB@JISCMAIL.AC.UK> Envoyé: Vendredi 21 Février 2020 15:24:53 Objet: [ccp4bb] ITC Stoichiometry
Dearall, Apologiesfor an off-topic question. There are two proteins- A(monomer) and B(hexamer).As per reports, one molecule of A(monomer) should bind to one molecule of B(hexamer).In order to show the interaction between the two proteins through ITC, A istaken in the syringe and B is taken in the cell. What kind of stoichiometry valuesshould be expected? Ilook forward to your responses. Manythanks in advance. Best, Angshu To unsubscribe from the CCP4BB list, click the following link: https://www.jiscmail.ac.uk/cgi-bin/webadmin?SUBED1=CCP4BB&A=1 To unsubscribe from the CCP4BB list, click the following link: https://www.jiscmail.ac.uk/cgi-bin/webadmin?SUBED1=CCP4BB&A=1 ######################################################################## To unsubscribe from the CCP4BB list, click the following link: https://www.jiscmail.ac.uk/cgi-bin/webadmin?SUBED1=CCP4BB&A=1