the thing that is outstanding here is that you are still
condescendingly explaining where he is wrong ;) Crack a statistics
text, dude.

If the coin toss is a reference model, it's yours, and it sucks. Let
me scroll up and see what your exact argument is, and see if I can't
straighten this out. I think you may need somehting like the drake
equation.

On 11/12/06, Gruss Gott <[EMAIL PROTECTED]> wrote:
> > RoMunn wrote:
> > No, no, no. if 1 in 167 people is killed each year,
>
> Here's where you're stuck:  There's a difference between the odds of a
> favorable outcome in one iteration and that favorable outcome
> **without losing**  **multiple times in a row**.  So the odds of death
> do indeed double the longer you stay because you're extending the odds
> of a favorable outcome *without dying* across 2 years, not 1.
>
> If one could die in year 1 and then return from the dead to fight
> again in year 2, you'd be right.  But that's not possible so you're
> wrong.  I'll show you the math again:
>
> Every time a soldier goes into combat they have **TWO** probabilities
> that are important:
>
> (1.) The probability that they will die **on any given day**.  This is
> where you and Dana are stuck.
>
> (2.) The probability of NOT dying **multiple days in a row**.  If you
> can't make it multiple days in a row WITHOUT DYING, you can't live and
> return to combat.
>
> Therefore when you calculate the probability you MUST calculate the
> probability of the favorable outcome multiple days in a row.  Here are
> those calculations:
>
> ..999983^365=.993814 This is the calculation that shows the probability
> of living 365 days in a row.  It says that, based on current casualty
> rates, that probability is 99.3814%
>
> 0.999983^730 = 0.987667  This is calculation that shows the
> probability of living 2x365=730 days in a row. That probability is
> 98.7667%
>
> 98.7667% < 99.3814% which means that the longer you stay in combat the
> more likely you are to die.
>
> Now let's address your concern:
> --------------------------------------------------------
> The probability of living is 98.7667 so 1 - 0.987667 = 0.012333 or
> 1.2% which is probability of dying.
>
> That means 12.33 / 1000 will die based on current rates or
> (12.33/12.33) / (1000/12.33) = 1/81.103
>
> or 1 in 81 **of those in combat 2 years in a row** will die.
>
> Here's the key: [listen closely now]
>
> Of those that are in combat for 730 days in a row, 1 in 81 will die.
> Or, put another way, those that stay in combat 730 days in a row are
> more likely to die than those that are in combat only 365 days in a
> row.
>
> 

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