*smacks forehead* Now I feel stupid. You are absolutely right. Must need caffeine or something.
--ben Barney Boisvert wrote: > The carat inside the class negates the class. So the RE returns the first > character that's not a CR or LF (the first character we don't want to > count), subtracts one for that character, and then divides by two. I don't > need to mess with the start of the string, because that's the way REfind > works by default (can be overridden by passing in the 'start' parameter). > > Given the string > CR & LF & CR & LF & CR & LF & "hello" > REfind() will return 7 (for the 'h'), minus 1 is 6, divide by 2 is three, > which is the number of CRLF pairs. > > barneyb > > >>-----Original Message----- >>From: Ben Doom [mailto:[EMAIL PROTECTED] >>Sent: Thursday, September 25, 2003 12:25 PM >>To: CF-Talk >>Subject: Re: Counting CRLF >> >> >>There are 2 problems with what you wrote. The carat inside the class >>will accept carats, also. The carat not outside the class means that it >>won't stop at the beginning. So, this will return the position of the >>first carat, cr, or lf that it finds, divided by two. >> >>Mine actually returns the string of cr/lfs leading, finds the len, and >>divides by 2 to (hopefully) return the correct number of linebreaks. >> >>--ben > > > ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~| Purchase from House of Fusion, a Macromedia Authorized Affiliate and support the CF community. http://affiliates.macromedia.com/t.asp?id=2439&p=go/dr_text_aff1 Message: http://www.houseoffusion.com/lists.cfm?link=i:4:138530 Archives: http://www.houseoffusion.com/lists.cfm?link=t:4 Subscription: http://www.houseoffusion.com/lists.cfm?link=s:4 Unsubscribe: http://www.houseoffusion.com/cf_lists/unsubscribe.cfm?user=89.70.4
