> the first matching word (will always be 2), NOT the wordcount.
Damn, yes, you're right. I was thinking perl regex. Sorry!
#!/usr/bin/perl
$word = "the";
$string = "q giw fieo the nigeow the woeifnw io fmewo the miwo";
@wordarray = $string =~ /[^[:alpha:]]($word)[^[:alpha:]]/g;
print scalar(@wordarray) . "\n";
:o\
Tim.
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