ListFind doesn't accept a 'index' argument. The 3rd argument is the
delimiter, which defualts to a comma. Now, the second example you used,
where you passed 1 as the 3rd arg, should return 0 since 1 doesn't exist in
the list.
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- ListFind() weirdness Seth Johnson
- Re: ListFind() weirdness Marlon Moyer
- Re:ListFind() weirdness Seth Petry-Johnson
- RE: ListFind() weirdness Bryan F. Hogan
- RE: ListFind() weirdness Raymond Camden
- RE: ListFind() weirdness Bryan F. Hogan
- Re: ListFind() weirdness Marlon Moyer
- RE: ListFind() weirdness Raymond Camden
- Re: ListFind() weirdness Chris Stoner
- RE: ListFind() weirdness Schuster, Steven
- RE: ListFind() weirdness Schuster, Steven
- RE: ListFind() weirdness Dave Watts
- RE: ListFind() weirdness Schuster, Steven