I would think it should pass back 1 since it will treat the string as a
1 element string regardless of what delimiter you specify if it can't
find that delimiter.
Raymond Camden wrote:
> ListFind doesn't accept a 'index' argument. The 3rd argument is the
> delimiter, which defualts to a comma. Now, the second example you used,
> where you passed 1 as the 3rd arg, should return 0 since 1 doesn't
> exist in
> the list.
>
>
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- RE: ListFind() weirdness Raymond Camden
- RE: ListFind() weirdness Bryan F. Hogan
- RE: ListFind() weirdness Marlon Moyer
- RE: ListFind() weirdness Raymond Camden
- Re: ListFind() weirdness Chris Stoner
- RE: ListFind() weirdness Schuster, Steven
- RE: ListFind() weirdness Schuster, Steven
- RE: ListFind() weirdness Dave Watts
- RE: ListFind() weirdness Schuster, Steven