rsmith added a comment. > In https://reviews.llvm.org/D53949#1282884, @regehr wrote: > >> The C99 standard (6.5.3.1.2) appears to be very clear on this point: "The >> expression ++E is equivalent to (E+=1)." > > > That is clearly not what clang is doing here.
How so? E += 1 is equivalent to E = E + 1, which effectively performs the arithmetic in the promoted type, which is what clang does. (The potential promotion from E to int can't change the value, but the implicit conversion from the type of E + 1 to the type of E can, if E's type is not a promoted type.) Repository: rC Clang https://reviews.llvm.org/D53949 _______________________________________________ cfe-commits mailing list cfe-commits@lists.llvm.org http://lists.llvm.org/cgi-bin/mailman/listinfo/cfe-commits
