Moved the thread to chat. /Erling
On 2017-12-20 19:32, Erling Hellenäs wrote:
Hi all!
Thanks, I will look into the details tomorrow, but yes , and I see a
number of problems with this as mentioned in this post:
http://www.jsoftware.com/pipermail/programming/2017-December/050179.html
In this thread I am trying to discuss strategies to solve these problems.
Pesch[1986] might give us relevant information about this. Thanks!
Cheers,
Erling Hellenäs
On 2017-12-20 17:21, Jose Mario Quintana wrote:
For this to happen J functions have to be defined for handling
arrays of
nothing?
I have not followed this thread, or any other recent thread, closely but
this might shed some light:
"
Zero Frame. If the frame contains 0 (as in 3 *"1 i. 0 4), there are no
argument cells to apply v to, and the shape of a result cell (the
value of
sir) is indeterminate. Pesch [1986] describes a variety of
strategies to
address this problem. In J, the shape is calculated if v is uniform (see
below); otherwise v is applied to a cell of fills.
"
Rank and Uniformity Roger K.W. Hui
http://www.jsoftware.com/papers/rank.htm
I hope it helps
On Wed, Dec 20, 2017 at 4:03 AM, Erling Hellenäs
<[email protected]>
wrote:
Hi all !
Could we avoid doing these peculiar things in the rank operator if we
enabled the handling of arrays of nothing?
The verb injected in Rank would then have to give a valid result for an
array of nothing?
For this to happen J functions have to be defined for handling
arrays of
nothing?
Would it be possible to define an algebra for the handling of arrays of
nothing?
Could this be the same as enabling missing data?
Cheers,
Erling
Den 2017-12-20 kl. 09:46, skrev Erling Hellenäs:
This is a mathematical concept: https://en.wikipedia.org/wiki/
Empty_product /Erling
Den 2017-12-20 kl. 09:39, skrev Erling Hellenäs:
*/i.0
1
Here the interpreter automatically adds a 1 to get this peculiar
result.
/Erling
Den 2017-12-19 kl. 20:01, skrev Raul Miller:
An empty tank zero array would be inconsistent.
The number of elements in an array is the product of its
dimensions, and
the multiplicative identity is 1, not 0.
Thanks,
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