Well, what's a computation?  Is y=x a computation, where x is a number,
including an irrational?  I thought we were talking about mathematical
numbers?

Proof of my other assertions:  an interval (x,y) (or [x,y) or (x,y] or
[x,y]) has a 1-1 mapping onto (0,1), and in (0,1) there are a countable
number of rationals and an uncountable number of irrationals.  The mapping
is a linear mapping and the parameters are easy to figure out.



On Sat, Mar 30, 2019 at 6:22 PM William Tanksley, Jr <[email protected]>
wrote:

> Roger Hui <[email protected]> wrote:
> > I assume you are talking about mathematical numbers rather than
> > finite-precision floating point representations of same.  In that case,
> the
> > first claim (countable number of irrationals can appear as the limit of
> > computations) is false.
>
> There are only countably many computations -- Godel's correspondence.
> So there are only countably many irrationals which can be the limit of
> a computation (that is, a non-terminating computation, such as
> Chatin's Omega). Chatin proved this result, on the way to proving that
> the only irrationals which are uncountable are the ones we cannot work
> with in any way.
>
> > The second claim (some pairs of rationals have no
> > irrationals between them) is false.
>
> Good proof, I'm persuaded.
>
> -Wm
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