Yes...

Another question is whether more than one amoeba can occupy a single position.

I imagine that this can happen, because there's no mention of
divisions being blocked by crowding. But, it's worth verifying that
assumption...

Thanks,

-- 
Raul

On Sun, Sep 5, 2021 at 10:00 AM 'Mike Day' via Chat <[email protected]> wrote:
>
> Aaaaah....
>
> Thanks all.  I suppose the remark, that there are N+1 amoebas after N 
> divisions, was the clue,  as well as your various examples.
>
> I’d thought they meant that all members of a generation spawn offspring; 
> evidently only one may reproduce at each stage.  Onwards and downwards.
>
> Thanks again,
>
> Mike
>
> Sent from my iPad
>
> > On 5 Sep 2021, at 12:12, 'Michael Day' via Chat <[email protected]> wrote:
> >
> > The good news:  2 new problems yesterday after a lull for several months.
> > The bad news (for me): I don't understand them!
> >
> > ... which is often the case,  but here,  I don't even get the Mickey Mouse 
> > case.
> >
> > It's not done to "spoil" these problems for others,  but I don't think it's 
> > cheating to
> > invite an explanation for how C(2) = 2 for problem 762.  Once I understand 
> > what they
> > want I can go on and (probably not) be able to solve it for myself.
> >
> > As I mis-understand it, the starting position is (0,0) and there's only one 
> > state at each generation.
> > Where does the multiplicity arise?
> >
> > I should post my query in their Clarifications Forum,  but don't fancy 
> > being trolled there - much
> > better to be teased by fellow J(oker)s.
> >
> > The original of problem 762 can be found here:
> >    https://projecteuler.net/problem=762
> >
> > Here's a copy, modified to non-graphics, roughly as pasted into my 
> > proto-script:
> >
> > ... better in a fixed width font:
> > NB. Problem 762
> > NB. Consider a two dimensional grid of squares. The grid has 4 rows but 
> > infinitely many columns.
> >
> > NB. An amoeba in square (x, y) can divide itself into two amoebas to occupy 
> > the squares (x+1,y) and
> > NB. (x+1,4|y+1), provided these squares are empty.
> >
> > NB. The following diagrams show two cases of an amoeba placed in square A 
> > of each grid. When it divides, it is
> > NB. replaced with two amoebas, one at each of the squares marked with B:
> >
> > NB. (origin at J matrix index 3 0)
> > NB.    ('abb' (3 2 3, each 0 1 1) } 4 6 $ '.'),.(4 4$' '),. 'abb' (0 0 3, 
> > each 3 4 4) } 4 6 $ '.'
> > NB. ......    ...ab.
> > NB. ......    ......
> > NB. .b....    ......
> > NB. ab....    ....b.
> >
> > NB. Originally there is only one amoeba in the square (0, 0). After N 
> > divisions there will be N+1 amoebas
> > NB. arranged in the grid. An arrangement may be reached in several 
> > different ways but it is only counted once.
> > NB. Let C(N) be the number of different possible arrangements after N 
> > divisions.
> >
> > NB. For example, C(2) = 2, C(10) = 1301, C(20)=5895236 and the last nine 
> > digits of C(100) are 125923036.
> > NB. Find C(100,000), enter the last nine digits as your answer.
> >
> > One for Joseph Turco,  perhaps;  and thanks for any,  non-spoiler, tips!
> >
> > Mike
> >
> > --
> > This email has been checked for viruses by Avast antivirus software.
> > https://www.avast.com/antivirus
> >
> > ----------------------------------------------------------------------
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> ----------------------------------------------------------------------
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