The answer has to do with the IEEE 802.3 standards. There are actually two
models how to calculate a "valid" ethernet network for 10Base2/5.
Model 1: Simplified model widely known as 5-4-3 rule.
Model 2: Calculation of Roundtrip delay (<576 bit times) and Interframe Gap
shrinkage (50 bit times)
In model 1, there can be 5 segments connected by 4 repeaters, but only 3 can
have stations on them (half duplex mode), the other 2 MUST BE link segments
(full duplex, for instance fiber).
Check out this excellent Website of the Ethernet guru: Charles Spurgeon.
http://www.ots.utexas.edu/ethernet/ethernet.html the entrance to his website
http://www.ots.utexas.edu/ethernet/10quickref/ch7qr_5.html#HEADING4
outlines model 1
http://www.ots.utexas.edu/ethernet/10quickref/ch7qr_6.html#HEADING5 outlines
model 2
This question came up some time ago (January 2000) also, so check the
archives for more reactions to your question.
Willy Schoots
-----Original Message-----
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]On Behalf Of
Cisco man
Sent: Thursday, May 25, 2000 5:24 AM
To: [EMAIL PROTECTED]
Subject: 5-4-3 Rule
Hi everyone
Can someone pls explains the reason behind the limits of 5 segments and why
only 3 segments can be populated with nodes?
Thanks
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