You have the correct formula, the statement you need if you use policing
should look something like this.

police 3000000 375000 conform-action transmit exceed-action drop 

You may want to consider shaping instead of policing as it will most likely
give you better performance. With policing or shaping all traffic that
exceeds the rate is dropped. The drops will cause the TCP windows to reset
for each flow that the exceeding packets belong to and applications to slow.
When using policing, as traffic burst it is more likely to reach the limit
which can cause drops and spikes in the traffic pattern. With shaping the
traffic is buffered in an attempt to spread the traffic out so that it
doesn’t reaching the limit. Shaping tries to avoid drops and TCP
window resets, which in turn can provide better utilisation of bandwidth.
The config would look something like this.


policy-map vpn-policy1
  class good
   bandwidth 3000
   shape average 3000000 3000000 0

regards, Mike



Erek Riccobuano wrote:
> 
> I want to police traffic on a 3550 so that one port is set to
> 3Mbs another is 10Mbs and another is 1.5Mbs. How do I calculate
> the burst?
> 
> The CCO give a formula like below but I can't make sense of it.
> 
> Burstmin (bits) = Rate (bps) / 8000 (1/sec) 
> 
> My configs so far are below. Am I going about this the right
> way? All I want to do is limit each customer to the bandwidth
> agreed upon.
> 
> access-list 100 permit ip any any
> 
> class-map match-all customer1
>  match access-group 100
> 
> policy-map customer1
>   class customer1
>     police 3000000 ???? exceed-action drop
> 
> interface FastEthernet0/16
>  service-policy input customer1
> 
> Thank you,
> 
> Erek
> 




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