Here is how i remember the host range, this is a quote from
a Cisco text (I dont remember which one since i made a
flash card of the info)
"Once you have computed the subnet mask to figure the valid
subnets use the formula
256 - subnet mask = 1st net."
Exp: 4 subnets needed:
mask would be 11100000 = 224
256 - 224 = 32 = first useable net
so that gives net address = 32, 1st host = 33, last host =
62, broadcast = 63.
Hope this helps
Rick
On Mon, 4 Sep 2000, Circusnuts wrote:
>Date: Mon, 4 Sep 2000 11:01:14 -0100
>From: Circusnuts <[EMAIL PROTECTED]>
>To: [EMAIL PROTECTED]
>Subject: Quick Remedial Subnetting Theory (not hard I swear)...
>
>I broke out the CCNA book, to practice readings for a couple of up & coming
>interviews (this week). Here is what I have forgotten :-) OK- I can
>calculate the mask (no issues here), but I cannot logically figure out how I
>would start the host addressing. Case in point (bare with me, this all
>looks soooo familiar it might just set back in while writing this :-)
>
>192.16.12.0 is my given class C
>
>I need 10 users (hosts- 11 counting the Ethernet Interface)
>
>So this means I must take 2 to the 4th (16-2= 14 usable) on the mask side &
>that leaves me with 2 to the 4th on the Host addressing side (same 14
>usable).
>
>How to I proceed with the first to last IP's available... i.e.
>
>My nature tendency, it to look @ things this way...
>192.16.12._ to _, does this mean I am now in the 16's if I recall.
>192.16.12.1 thru 15, 192.16.12.16 thru 31, 192.16.12.32 thru 63, etc...
>
>The book I have (full of typo's) starts with a 192.16.12.144 as the first
>address...
>
>Hope this is not too confusing...
>Thanks All !!!
>Phil
>
>
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