no not really.
what you will want to do is configure null interfaces on those routers tho...( i think)
00001010 -- 10
00010000 -- 16
00000000 -- 0
this is the third octet, and all the bits are the same up to 19.
so yes, your aggregation is correct. (i think)
- Peter (i think, therefore i am not always sure...)
>first , to be able to do supersubneting you need to have consecutive
>network
>
>
>
>"A.Strobel" wrote:
>>
>> What is the correct supernet for the followings:
>>
>> 172.29.10.0 255.255.255.128
>> 172.29.16.64 255.255.255.192
>> 172.29.0.0 255.255.255.224
>>
>> is my calculation of 172.29.0.0/19 correct?
>>
>> Thanks,
>>
>> A. Strobel
>>
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