It would appear to me that by the statement 172.16.0.0/19 they are stating a
major net rather than one of the subnets created by the masking. If you look
carefully at the answers, D is the only one that can be right because it is
the only one that qualifies as a host address. A) 172.16.32.0 = a subnet
address, B) 172.16.64.0 = a subnet address, C) 172.16.63.255 = a broadcast
address within a subnet, D) 172.16.80.255 = a host address within a subnet.
If I am wrong, it wouldn't be the first time. but that's what I see.
Adam Hickey
[EMAIL PROTECTED]
----- Original Message -----
From: "Bruce" <[EMAIL PROTECTED]>
Newsgroups: groupstudy.cisco
To: <[EMAIL PROTECTED]>
Sent: Wednesday, March 14, 2001 9:38 PM
Subject: Re: Sample CCNA test question..bogus?
> Tom, Thanks for your response but I beg to differ. I agree that answer D
> falls inside the range of the 64 subnet as you explain, but this is not
the
> question. The question asks for a valid host using 172.16.0.0/19, not
> 172.16.64.0/19
> By my reckoning, the valid host range is 172.16.0.1 to 172.16.31.254
>
> Regards,
> BR.
>
> "Tom Lisa" <[EMAIL PROTECTED]> wrote in message
> [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> > Well, since I'm not a qualified psychiatrist I don't want to comment on
> your mental
> > health, but there is a correct answer here. If we go to binary it all
> becomes clear.
> >
> > The /19 means that the first 19 bits are network/subnetwork bits and the
> remaining 13
> > bits are host bits. Therefore our mask would look like this:
> > 11111111.11111111.11100000.00000000
> >
> > Since the first two octects are identical, we can dispense with them and
> concentrate on
> > the first 3 bits of the third octet and the remaining host bits.
> >
> > Our subnet addresses would be as follows:
> >
> > X.X.00000000.00000000 = X.X.0.0 Hosts = X.X.0.1 - X.X.31.254 Bdcst =
> X.X.31.255*
> > *Assumes Subnet Zero Allowed
> > X.X.00100000.00000000 = X.X.32.0 Hosts = X.X.32.1 - X.X.63.254 Bdcst =
> X.X.63.255
> > X.X.01000000.00000000 = X.X.64.0 Hosts = X.X.64.1 - X.X.95.254 Bdcst =
> X.X.95.255
> > X.X.01100000.00000000 = X.X.96.0 Etcetera, Etcetera....
> > .
> > .
> > Etcetera (You get the picture)
> >
> > From this you can see that:
> > answer A is the "wire" address of the 32 subnet
> > answer B is the "wire" address of the 64 subnet
> > answer C is the Broadcast address of the 32 subnet
> > answer D falls within the valid host range for the 64 subnet and is
> correct.
> >
> > BTW, a good source for learning IP Addressing & subnetting is:
> www.learntosubnet.com
> >
> > HTH,
> > Prof. Tom Lisa, CCAI
> > Community College of Southern Nevada
> > Cisco Regional Networking Academy
> >
> >
> > Bruce wrote:
> >
> > > Q. Which one of the following is a valid host using the address of
> > > 172.16.0.0 /19?
> > >
> > > a. 172.16.32.0
> > >
> > > b. 172.16.64.0
> > >
> > > c. 172.16.63.255
> > >
> > > d. 172.16.80.255
> > >
> > > Which one and why?
> > >
> > > (I say none of them. Am I going mad?)
> > >
> > > _________________________________
> > > FAQ, list archives, and subscription info:
> http://www.groupstudy.com/list/cisco.html
> > > Report misconduct and Nondisclosure violations to [EMAIL PROTECTED]
> >
> > _________________________________
> > FAQ, list archives, and subscription info:
> http://www.groupstudy.com/list/cisco.html
> > Report misconduct and Nondisclosure violations to [EMAIL PROTECTED]
> >
>
>
> _________________________________
> FAQ, list archives, and subscription info:
http://www.groupstudy.com/list/cisco.html
> Report misconduct and Nondisclosure violations to [EMAIL PROTECTED]
>
_________________________________
FAQ, list archives, and subscription info: http://www.groupstudy.com/list/cisco.html
Report misconduct and Nondisclosure violations to [EMAIL PROTECTED]
