Bruce,
I disagree that the question is asking for a valid host in the 0 subnet. It is only
stating the network address and mask. Assuming classful addressing (as the CCNA exam
does), from that you have to determine what would be the valid host ranges given that
mask. Anyway, that is my interpretation of the question. BTW, where is this question
from?
Prof. Tom Lisa, CCAI
Community College of Southern Nevada
Cisco Regional Networking Academy
Bruce wrote:
> Tom, Thanks for your response but I beg to differ. I agree that answer D
> falls inside the range of the 64 subnet as you explain, but this is not the
> question. The question asks for a valid host using 172.16.0.0/19, not
> 172.16.64.0/19
> By my reckoning, the valid host range is 172.16.0.1 to 172.16.31.254
>
> Regards,
> BR.
>
> "Tom Lisa" <[EMAIL PROTECTED]> wrote in message
> [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> > Well, since I'm not a qualified psychiatrist I don't want to comment on
> your mental
> > health, but there is a correct answer here. If we go to binary it all
> becomes clear.
> >
> > The /19 means that the first 19 bits are network/subnetwork bits and the
> remaining 13
> > bits are host bits. Therefore our mask would look like this:
> > 11111111.11111111.11100000.00000000
> >
> > Since the first two octects are identical, we can dispense with them and
> concentrate on
> > the first 3 bits of the third octet and the remaining host bits.
> >
> > Our subnet addresses would be as follows:
> >
> > X.X.00000000.00000000 = X.X.0.0 Hosts = X.X.0.1 - X.X.31.254 Bdcst =
> X.X.31.255*
> > *Assumes Subnet Zero Allowed
> > X.X.00100000.00000000 = X.X.32.0 Hosts = X.X.32.1 - X.X.63.254 Bdcst =
> X.X.63.255
> > X.X.01000000.00000000 = X.X.64.0 Hosts = X.X.64.1 - X.X.95.254 Bdcst =
> X.X.95.255
> > X.X.01100000.00000000 = X.X.96.0 Etcetera, Etcetera....
> > .
> > .
> > Etcetera (You get the picture)
> >
> > From this you can see that:
> > answer A is the "wire" address of the 32 subnet
> > answer B is the "wire" address of the 64 subnet
> > answer C is the Broadcast address of the 32 subnet
> > answer D falls within the valid host range for the 64 subnet and is
> correct.
> >
> > BTW, a good source for learning IP Addressing & subnetting is:
> www.learntosubnet.com
> >
> > HTH,
> > Prof. Tom Lisa, CCAI
> > Community College of Southern Nevada
> > Cisco Regional Networking Academy
> >
> >
> > Bruce wrote:
> >
> > > Q. Which one of the following is a valid host using the address of
> > > 172.16.0.0 /19?
> > >
> > > a. 172.16.32.0
> > >
> > > b. 172.16.64.0
> > >
> > > c. 172.16.63.255
> > >
> > > d. 172.16.80.255
> > >
> > > Which one and why?
> > >
> > > (I say none of them. Am I going mad?)
> > >
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