Can you give examples of OSs that don't support all ones?
-----Original Message-----
From: Joshua Beining [mailto:[EMAIL PROTECTED]]
Sent: Thursday, March 22, 2001 2:44 PM
To: 'David A. Lauer'
Cc: '[EMAIL PROTECTED]'
Subject: RE: difficult ccna question
Technically yes. But like most things you cannot get something for free.
There is a price for subnetting which is that you loose the first subnet
(network - all zeros) and the last subnet (broadcast - all ones). Note that
with some routers you can configure them to use these subnets. But be
careful, because some OS's and devices do not react well to using then.
HTH.
-Joshua
-----Original Message-----
From: David A. Lauer [mailto:[EMAIL PROTECTED]]
Sent: Thursday, March 22, 2001 11:14 AM
To: [EMAIL PROTECTED]
Subject: RE: difficult ccna question
Wouldn't the first subnet be 172.16.0.0?
-----Original Message-----
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]On Behalf Of
Joshua Beining
Sent: Thursday, March 22, 2001 11:43 AM
To: 'Lowell Sharrah'
Cc: '[EMAIL PROTECTED]'
Subject: RE: difficult ccna question
Based on the subnet mask (255.255.192.0) subtract 256 from 192 which is 64.
Therefore 64 is your first subnet. To get the second subnet, add 64 to the
first subnet. To get the third add 64 to the second subnet and so on.
Continue in this fashion until you reach 192. Remember that you cannot use
the ranges 172.16.0.1 - 172.16.0.62 and 172.16.255.193 - 172.16.255.254
(network and broadcast respectively) unless your router is configured to do
so.
Subnet Host Range
1 172.16.0.65 - 172.16.0.126
2 172.16.0.129 - 172.16.0.190
3 172.16.0.193 - 172.16.0.254
4 172.16.1.1 - 172.16.1.62
5 172.16.1.65 - 172.16.1.126
6 172.16.1.129 - 172.16.1.190
7 172.16.1.193 - 172.16.1.254
8 172.16.2.1 - 172.16.2.62
9 172.16.2.65 - 172.16.2.126
10 172.16.2.129 - 172.16.2.190
.
.
.
.
.
.
1015 172.16.253.193 - 172.16.253.254
1016 172.16.254.1 - 172.16.254.62
1017 172.16.254.65 - 172.16.254.126
1018 172.16.254.129 - 172.16.254.190
1019 172.16.254.193 - 172.16.254.254
1020 172.16.255.1 - 172.16.255.62
1021 172.16.255.65 - 172.16.255.126
1022 172.16.255.129 - 172.16.255.190
-Joshua
-----Original Message-----
From: Lowell Sharrah [mailto:[EMAIL PROTECTED]]
Sent: Thursday, March 22, 2001 8:14 AM
To: [EMAIL PROTECTED]
Subject: RE: difficult ccna question
how do you know where the first subnet begins?
>>> Joshua Beining <[EMAIL PROTECTED]> 03/22/01 10:34AM >>>
Just remember the following fomulas:
(2^# of masked bits) - 2 = Total # of subnets
(2^# of unmasked bits - 2 = Total # of hosts
Based on this the correct answer is A.
-----Original Message-----
From: George [mailto:[EMAIL PROTECTED]]
Sent: Thursday, March 22, 2001 12:16 AM
To: [EMAIL PROTECTED]
Subject: difficult ccna question
if you have a class B network with a 10-bit subnet mask, how many subnet and
how many hosts do you have?
a. 1022 subnets, 62 hosts
b. 62 subnets, 8190 hosts
c. 8190 subnets, 254 hosts
d. 254 subnets , 126 hosts
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