In this scenario, I don't know why you use 128 for variance value. In short, you choose a value of variance such that this value multiplies by the best path should be GREATER than the alternate path you like to load balancing.
For this scenario, the bandwidth on R1-R2-R4 path is 3000K, bandwidth on R1-R3-R4 path is 1544K. Using a variance of 2 should load balance between the 2 paths. 1544k x 2 > 3000k Thomas N. ""kwock99"" wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... > I have tried some basic testing on the EIGRP load balancing. For simplicity, > I only set up 4 router in order to get equal cost load balancing. > > > LANA******R1 ----------R2 ----------R4******** LANB > | | > --------------R3------------ > > ***: Ethernet > ----: Wan > > If I use the default setting for the bandwidth and delay, I can get two > route from LAN A to LANB. > > R1--R2--R4 > R1--R3--R4 > > After I changed all the bandwidth of serial interface of R1, R2, R4 to > 3000Kbit (default is 1544kbit), I cannot get two route to LAN B, only the > best route appears (R1--R2--R4). It is normal. > > I key in the "variance 128" command in R1 in order to get two route, but it > failed. The parameter 128 is make sure that the R1 will take any alternate > route to LAN B because the metric of R1--R3--R4 must be less than 128 * > (metric of R1--R2--R4). > > Anyone have the idea? Thanks. > > Francis Message Posted at: http://www.groupstudy.com/form/read.php?f=7&i=23651&t=23623 -------------------------------------------------- FAQ, list archives, and subscription info: http://www.groupstudy.com/list/cisco.html Report misconduct and Nondisclosure violations to [EMAIL PROTECTED]
