Thanks,
Now you have to remember the DIV and MOD calculation you learned in school.
First, learn the values of each of the hex numbers.
If we take a max of four hex numbers (1 word, 2 bytes, 16 bits, etc.) you
have the following:
16^3 16^2 16^1 16^0
Doing a fast calculation gives us:
4096 256 16 1
That means that 1000 hex is 4096 dec. Got that? - Good!
With four numbers, you will have the range of 0000 to FFFF or 0 to 65535.
So if you have the decimal number 5000, you do the following:
Step 1: How many times does 4096 fit into 5000?
Answer = 1
Step 2: What's left?
Answer = 904
Step 3: How many times does 256 fit into 904?
Answer = 3
Step 4: What's left?
Answer = 136
Step 5: How many times does 16 fit into 136?
Answer = 8
Step 6: What's left?
Answer = 8
RESULT = 1388 hex is the same as 5000 dec.
Here's a practice story for you :-)
The 2750 with the 2989 64206 got a 3053 at the old 51966 where 43962 used to
190.
Hth,
Ole
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Ole Drews Jensen
Systems Network Manager
CCNP, MCSE, MCP+I
RWR Enterprises, Inc.
[EMAIL PROTECTED]
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
http://www.RouterChief.com
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
NEED A JOB ???
http://www.oledrews.com/job
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
-----Original Message-----
From: Persio Pucci [mailto:[EMAIL PROTECTED]]
Sent: Thursday, March 14, 2002 11:06 AM
To: [EMAIL PROTECTED]
Subject: Re: Hex to Decimal for the RD [7:38223]
Nice going, Ole!
Now, how about an easy way to convert decimal to hex without going through
binary (the way I learned)? :)
Persio
----- Original Message -----
From: "Ole Drews Jensen"
To:
Sent: Thursday, March 14, 2002 12:07 PM
Subject: RE: Hex to Decimal for the RD [7:38223]
> Hex is based on 16, where Dec is based on 10.
>
> When you see a value, no matter if it's in dec, hex, bin, or something
else,
> think of each number as being number 0 (the right one), 1, 2, 3, and so
on.
>
> If you for instance have the decimal value 579:
>
> Number 0 would be 9
> Number 1 would be 7
> Number 2 would be 5
>
> When you have decimal, the system is based on 10, so you will have to use
10
> to calculate your way to a result.
>
> The number 579 can be calculated this way:
>
> 9 * 10^0 = 9
> +
> 7 * 10^1 = 70
> +
> 5 * 10^2 = 500
> =
> Result = 579
>
> This seems pretty silly to calculate a value like that, but that's because
> we're used to see the value in a 10-based format.
>
> Okay, let's take your first 16-based (hex) value - F00.
>
> Again, from right to left:
>
> Number 0 is 0
> Number 1 is 0
> Number 2 is F (15 in decimal)
>
> Instead of using the number 10 to calculate, you will need to use the
number
> 16 to calculate:
>
> The value F00 in hex can be calculated this way:
>
> 0 * 16^0 = 0
> +
> 0 * 16^1 = 0
> +
> F * 16^2 = 3840
> =
> Result = 3840
>
> You can with hex make words if that helps you remember the value, as long
as
> you do not use letters above F.
>
> For instance, the value ABBA would be a good one to use for a Swedish
> Ericsson Server (if they exist), and the value would be calculated like
> this:
>
> A * 16^0 = 10
> +
> B * 16^1 = 176
> +
> B * 16^2 = 2816
> +
> A * 16^3 = 40960
> =
> Result = 43962
>
> If this is still a little confusing, the let's continue with your second
> value, and break it up a little more:
>
> 2F2
>
> First number is 2 (2 decimal) which must be multiplied by 16^0 (1).
>
> The result is 2.
>
> Second number is F (15 decimal) which must be multiplied by 16^1 (16).
>
> The result is 240.
>
> The third number is 2 (2 decimal) which must be multiplied by 16^2 (256).
>
> The result is 512.
>
> The final result will therefore give us 2+240+512 = 754 decimal.
>
> Conversions between all systems other than decimal is much easier, because
> they are based on what I call double up. If you start with binary. Binary
is
> based on 2. When you double up, you will get 4. Next time you will get 8.
8
> is the number that Octal is based on, but that's not used much anymore.
Next
> time you will get 16. 16 is the number that Hex is based on.
>
> Now, you can see that going from hex to binary will be easier. Hex numbers
> goes from 0 to 15, and binary goes from 0 to 1. So that means that four
> binary numbers matches one hex number.
>
> An example:
>
> The hex number F00 again. If you take each number and convert it to
binary,
> it is much easier.
>
> 0 = 0000
> 0 = 0000
> F = 1111
>
> Result = 1111 0000 0000
>
> You can now convert the binary number to octal, which is based on three
> binary numbers instead of four.
>
> First, put spaces in between every third to make it easier:
>
> 111 100 000 000
>
> You can see that it is the same binary number as above, but it looks
> different now.
>
> Now convert to Octal:
>
> 000 = 0
> 000 = 0
> 100 = 4
> 111 = 7
>
> Octal result = 7400
>
> Some people prefer to use binary when converting from hex to decimal.
>
> Again, let's take the F00.
>
> >From Hex to Bin:
>
> F 0 0 = 1111 0000 0000
>
> Let's split the binary numbers up:
>
> 0 * 2^0 (1) = 0
> 0 * 2^1 (2) = 0
> 0 * 2^2 (4) = 0
> 0 * 2^3 (8) = 0
> 0 * 2^4 (16) = 0
> 0 * 2^5 (32) = 0
> 0 * 2^6 (64) = 0
> 0 * 2^7 (128) = 0
> 1 * 2^8 (256) = 256
> 1 * 2^9 (512) = 512
> 1 * 2^10 (1024) = 1024
> 1 * 2^11 (2048) = 2048
>
> RESULT = 3840
>
>
> If you look at the first calculation we did in the beginning, you can see
> that I came to the same result.
>
> Hth,
>
> Ole
>
> ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
> Ole Drews Jensen
> Systems Network Manager
> CCNP, MCSE, MCP+I
> RWR Enterprises, Inc.
> [EMAIL PROTECTED]
> ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
> http://www.RouterChief.com
> ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
> NEED A JOB ???
> http://www.oledrews.com/job
> ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
>
>
>
>
>
> -----Original Message-----
> From: Mckenzie Bill [mailto:[EMAIL PROTECTED]]
> Sent: Thursday, March 14, 2002 8:02 AM
> To: [EMAIL PROTECTED]
> Subject: Hex to Decimal for the RD [7:38223]
>
>
> Could someone help me get a clear understanding of converting the hex
number
> to a nice decimal ring number or bridge number.
>
> Two examples that have me stumped are:
>
> F00 and 2f2.
>
> Thanks Everyone in advance.
Message Posted at:
http://www.groupstudy.com/form/read.php?f=7&i=38265&t=38223
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