Here is how I understand it: Let's say 0110.1234.5678 is represented on the Token Ring side. Then, 8008.482c.6a1e is the source MAC address as it would be represented on the Ethernet segment. This is because you're going from Token Ring to Ethernet and bit (opposite or reverse) swapping takes place. How is this done? First write out the source MAC address in binary (hopefully, this shows up like I typed it):
0 1 1 0 1 2 3 4 5 6 7 8 0000 0001 0001 0000 0001 0010 0011 0100 0101 0110 0111 1000 \ / \ / \ / \ / \ \ / \ / \ / \ / \ 1000 0000 0000 1000 0100 1000 0010 1100 0110 1010 0001 1110 8 0 0 8 4 8 2 C 6 a 1 e As shown above, bit swap each bit shown by the arrows. So, for example, 0001 becomes 1000 after the swap, 0011 becomes 1100, 0111 becomes 1110, etc. You'll notice that 0110 and 0000 stay the same because writing them backwards gives you the same result. Shawn K. -----Original Message----- From: Mckenzie Bill [mailto:[EMAIL PROTECTED]] Sent: Tuesday, March 19, 2002 12:31 PM To: [EMAIL PROTECTED] Subject: Bit Swapping [7:38823] Can anyone give me an easy explain how to figure out bit swapping from Token Ring to Ethernet? I reviewed the Token Ring Whitepaper, but there is such a short section on it. Thanks, Bill Message Posted at: http://www.groupstudy.com/form/read.php?f=7&i=38841&t=38823 -------------------------------------------------- FAQ, list archives, and subscription info: http://www.groupstudy.com/list/cisco.html Report misconduct and Nondisclosure violations to [EMAIL PROTECTED]