Actually...4 bits makes 16 combinations....( 2 to the power of 4 = 16 )
( 4 positions with 2 possibilities per bit position )

Dain
""Andy Hoang""  wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> I would say 8 is correct.  4 bits make 8 combinations.
>
> -----Original Message-----
> From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]On Behalf Of
> Michael L. Williams
> Sent: Monday, July 08, 2002 8:15 PM
> To: [EMAIL PROTECTED]
> Subject: Re: Class C summarization question [7:48367]
>
>
> I would say 16 as well.....
>
> Mike W.
>
>
> "Dain Deutschman"  wrote in message
> [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> > I'm confused about a practice question for BSCN that I came across:
> >
> > Your routing tables are getting very large and you need to configure
route
> > summarization. How many class C internet addresses can you summarize
with
> a
> > /20 CIDR block?
> >
> > Answer: 8
> >
> > Would it not be 16? Where am I going wrong?
> >
> > --
> > Dain Deutschman
> > CNA, MCP, CCNA
> > Data Communications Manager
> > New Star Sales and Service, Inc.




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