Great, detailed explanation !

Thanks!

Brett Michael Spunt
Internetworking Engineer
CCNP,MCSE,CIPT,CCNA,MCP,CNA,A+
818 734-6880 ext.59
[EMAIL PROTECTED] 






-----Original Message-----
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]On Behalf Of
Haakon Claassen (hclaasse)
Sent: Sunday, September 29, 2002 1:28 PM
To: [EMAIL PROTECTED]
Subject: RE: Filter odd routes via wildcard bits - How?? [7:54496]


Hi

Just do the binary  calculus

0.0.254.255  is 0000 0000. 0000 0000. 1111 1110 . 1111 1111

apply that to your prefix 172.168.1.0


the first two bytes (172 and 168) will have to match
and  the last bit of the 3rd byte needs to be 1

so that would be 172.168.1  .3   .5   .7 .8
in the other case .0 .2 .4 .6  you have a 0 at that position


These maches the routes to be denied (the odd ones)
And the even gets permitted by the permit any



In short
   subnet masks need to be contiguous 1 ones followed by contiguous
zeros
   wildcards don't   1010 0111 . 1111 0000 . 1110 0111 . 1010 1010  is a
valid wildcard ( 167.240.199.170)

regs




Haakon Claassen
EMEA - IT Transport Services -WAN

Cisco Systems
De Kleetlaan 6b - Pegasus Park
B-1831 Diegem (Belgium)



-----Original Message-----
From: Cisco Nuts [mailto:[EMAIL PROTECTED]]
Sent: zondag 29 september 2002 20:59
To: [EMAIL PROTECTED]
Subject: Filter odd routes via wildcard bits - How?? [7:54496]

Hello,

I am trying to understand how a wildcard mask of 0.0.254.255 filters odd

routes so that only even routes get across the router.

Ex. If you have routes for 172.168.1.0/24, 2.0/24, 3.0/24, 4.0/24,
5.0/24,
6.0/24 and you have an access-list of:

#access-list 11 deny 172.168.1.0 0.0.254.255
#access-list 11 permit any

And a:

#distribute-list 11 out

This will allow only: 172.168.2.0/24, 4.0/24 and 6.0/24 routes out.

Anyone can kindly explain the magic of this 0.0.254.255 wildcard?

Thank you.

Sincerely.


BTW: Anyone know the link on this on CCO?








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