Maybe you want this:

user=>(map (partial reduce +) '((1 2) (2 3) (3 4)))
(3 5 7)

Maybe not.

On Aug 19, 2:56 am, simon <fre...@gmail.com> wrote:
> (apply map + '((1 2) (2 3) (3 4)))
>
> produces result: (6 9)
>
> Could anyone explain a little more detail how the result being
> produced?
> Though I checked the source of 'apply' function but still not clear
> how this piece of code eval.
>
> Thank you in advance.
> -Simon
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