Hi Clojurians, I have some conceptual questions on the sequence abstraction. I understand that (seq coll) will give me a "sequence". coll maybe be a list, vector, map, set, LazySeq or nil.
1. In case coll is a LazySeq why does (seq coll) realize its first element? I thought seq just did a type conversion and all of list, vector .. etc implemented Seqable or something. 2. Why is there no other way to determine an empty coll except (not (seq coll)). - Thanks -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
