On Sunday, April 14, 2013 5:30:13 PM UTC+1, Jonathan Fischer Friberg wrote:
Calling fib just creates a new function, no values > are calculated. So you're measuring the time > it takes to create a function, and not the calculation > of fibonacci numbers. > > Oops ;) Of course you are right. The amazing thing is that the times I observed fitted somehow the situation (the first (fib 30) call taking much more time than the others, the third call more than the second and fourth) that I was tricked into believing the calculations were being done and wasn't careful enough ... btw, why does such a thing happen if in all four cases only a function is being created as you say? And given that a simple let as follows cannot be used: (let [fib (memoize #(if (or (zero? %) (= % 1)) 1 (+ (fib (- % 1)) (fib (- % 2)))))] ...) Is this an example of something that cannot be elegantly expressed without a letrec, and for which letfn is not enough as a substitute? Regards, Paulo -- -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en --- You received this message because you are subscribed to the Google Groups "Clojure" group. To unsubscribe from this group and stop receiving emails from it, send an email to clojure+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out.