Try this version.
user> (defn gen-crypto [] (let [chars #(->> (iterate inc %) (map char) (take 26)) upper (chars 65) lower (chars 97) digit (take 10 (chars 48)) [sl su sd] (map shuffle [lower upper digit]) encrypt (apply merge (map hash-map (concat lower upper digit) (concat sl su sd)))] (comp #(apply str %) (fn [x] (map #(encrypt % %) x))))) #'user/gen-crypto user> ((gen-crypto) "1 for me, 2 for you.") "8 hau yi, 3 hau raf." user> ((gen-crypto) "1 for me, 2 for you.") "7 uga xi, 5 uga ygn." user> ((gen-crypto) "1 for me, 2 for you.") "0 qhf oz, 8 qhf rhl."
11.06.2013, 11:58, "Shannon Severance" <s...@s53.me>:
Thank you for your example. I especially like doing sl, su, sd in one line.However:user=> ((gen-crypto) "1 for me, 2 for you.")"1 zdu gy, 2 zdu fdx."The numbers are coming through without translation. I believe defining digit as:user=> (map #(char (+ 48 %)) (range 10))(\0 \1 \2 \3 \4 \5 \6 \7 \8 \9)will fix that issue. Or (map char (range 48 58))
On Monday, June 10, 2013 7:42:45 PM UTC-7, Kelker Ryan wrote:Here's my re-write.user> (defn gen-crypto [] (let [atoz (range 65 91) upper (map char atoz) lower (map #(char (+ % 32)) atoz) digit (range 10) [sl su sd] (map shuffle [lower upper digit]) encrypt (reduce conj (map hash-map (concat lower upper digit) (concat sl su sd)))] (fn [s] (apply str (map #(encrypt % %) s))))) #'user/gen-crypto user> ((gen-crypto) "abc") "ghm" user> ((gen-crypto) "abc") "efz"11.06.2013, 10:31, "Shannon Severance" <s...@s53.me>:> I'm new to Clojure, but with some lisp experience, I've dabbled in Scheme for a few years. Used Racket earlier this year for a couple of sectoins of a MOOC. And occasionally write Emacs lisp.>> The idea is to create cyptograms. These are word puzzles using simple ciphers, and not meant for keeping real secrets.>> ;; -> (String -> String)> ;; Returns a function that takes a string and produces a cryptogram.> ;; Multiple calls to make-crypto will return different cryptos> ;; each with different substitution keys. Multiple calls to a given> ;; crypto returned by make-crypto will use the same substitution key.>> (defn make-crypto []> (let [lower (seq "abcdefghijklmnopqrstuvwxyz")> upper (seq "ABCDEFGHIJKLMNOPQRSTUVWXYZ")> digit (seq "0123456789")>> shuffled-lower (shuffle lower)> shuffled-upper (shuffle upper)> shuffled-digit (shuffle digit)>> encrypt (reduce> conj> (map (partial assoc {})> (concat lower upper digit)> (concat shuffled-lower shuffled-upper shuffled-digit)))]> (fn [s]> (apply str (map #(encrypt % %) s)))))>> To me, it looks like too much code in defining the encrypt map. But I do not know how.>> -- Shannon>> --> --> You received this message because you are subscribed to the Google> Groups "Clojure" group.> To post to this group, send email to clo...@googlegroups.com> Note that posts from new members are moderated - please be patient with your first post.> To unsubscribe from this group, send email to> For more options, visit this group at> ---> You received this message because you are subscribed to the Google Groups "Clojure" group.> To unsubscribe from this group and stop receiving emails from it, send an email to clojure+u...@googlegroups.com.> For more options, visit https://groups.google.com/groups/opt_out.
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