Good point... it was rather a sloppily done example.
If I wanted to do an iterative solution, I could have written:
(define (expt x n)
(define (iter x1 n1 result)
(cond ((= 0 n1) 1)
((= 1 n1) result)
(else (iter x1 (- n1 1) (* x1 result)))))
(iter x n x))
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