You can call functions within the macro body without the arguments to the
macro being evaluated. If this wasn't the case, you'd be very limited in
how you could transform code.

- James


On 17 March 2014 17:31, Yoav Rubin <yoavru...@gmail.com> wrote:

> I need to do it, as I need the arguments to remain not evaluated until
> they get to that private macro. That private macro does some work on the
> arguments before they get evaluated (the arguments themselves are
> s-expressions).
>
> Still, even if it is a private function - how can I call it from a macro
> that is called from another namespace?
>
>
> On Monday, March 17, 2014 4:19:19 PM UTC+2, James Reeves wrote:
>
>> Don't use a private macro: use a function that spits out an s-expression.
>>
>> - James
>>
>>
>> On 17 March 2014 06:02, Yoav Rubin <yoav...@gmail.com> wrote:
>>
>>> Hi All,
>>>
>>> I have a namespace that has two macros as part of its public API, and
>>> another macro that act as helpers for the public macro
>>>
>>> (defmacro helper-mac [arg1 arg2 f]
>>> ;; do stuff with f , arg1 and arg2
>>> )
>>>
>>> (defmacro m0 [arg1 arg2]
>>>    (priv-mac arg1 arg2 f1)
>>> )
>>>
>>> (defmacro m1 [arg1 arg2] (
>>>   (priv-mac arg1 arg2 f2)
>>> )
>>>
>>> f1 and f2 are just two functions.
>>>
>>> I would like to make the helper macro private (using  ^:private), but
>>> when I do it and call either m0 or m1 from another namespace, I get an
>>> exception saying that helper-mac is private.
>>>
>>> Is it possible to call from to a macro in another namespace when that
>>> macro is calling a private macro in its namespace?
>>>
>>> Thanks,
>>>
>>> Yoav
>>>
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>>
>>

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