Hi Cecil,
For precise timing benchmarks, use criterium [1].
For simple, gross timing, use
(map #(time (foo %)) numbers)
or to convert your code to something more functional (and including defns
for now and foo):
(defn now [] (. System currentTimeMillis))
(def numbers '(4 6 8 10))
(defn foo [n] (reverse (map #(* % %) (range (Math/pow n 5)))))
(count (foo 10))
(defn timed-foo [times n]
(let [start (now)]
(foo n)
(conj times (- (now) start))))
(reduce timed-foo [] numbers) => [0 0 4 14]
[1] https://github.com/hugoduncan/criterium
Regards,
Fergal
On Sat, Apr 12, 2014 at 1:13 PM, Cecil Westerhof <[email protected]>wrote:
> At the moment I have the following:
> (def numbers '(4 6 8 10))
>
> (doseq [number numbers]
> (foo number))
>
> The call foo generates some output, but I also want to save the time it
> took for the call to complete. At the moment I am thinking about
> something like:
> (def numbers '(4 6 8 10))
>
> (def ^:dynamic needed-times ())
> (doseq [number numbers]
> (let [start (now)]
> (foo number)
> (def ^:dynamic needed-times
> (cons (- (.getTimeInMillis (now))
> (.getTimeInMillis start))
> needed-times))))
>
> But it looks a 'little' cumbersome. Is there a better way to do this?
>
> Also if I need to use several points in time, do I keep nesting 'let',
> or is there a better way?
>
> --
> Cecil Westerhof
>
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--
Fergal Byrne, Brenter IT
Author, Real Machine Intelligence with Clortex and NuPIC
https://leanpub.com/realsmartmachines
<http://www.examsupport.ie>http://inbits.com - Better Living through
Thoughtful Technology
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