On 6 May 2014 13:09, Gary Trakhman <gary.trakh...@gmail.com> wrote:
> Last + butlast?
Yeah, there are a few more concise solutions to this problem if you're
familiar with the standard library:
(last (butlast coll))
(second (reverse coll))
(peek (pop (vec coll)))
And a more efficient loop-solution would just keep the previous value
stored until the end of the loop is reached:
(loop [prev nil, coll (seq coll)]
(if (next coll)
(recur (first coll) (next coll)
prev))
- James
>
>
> On Tuesday, May 6, 2014, Roelof Wobben <rwob...@hotmail.com> wrote:
>
>> Found the answer :
>>
>> (defn secondlast [coll]
>> (let [number 0
>> counter (- (count coll)2) ]
>> (loop [coll coll counter counter number number]
>> (if (= counter number)
>> (first coll)
>> (recur (next coll) counter (+ number 1))))))
>>
>> and without the loop there will be : (first(drop(reverse v))
>>
>> Roelof
>>
>>
>> Op dinsdag 6 mei 2014 13:36:53 UTC+2 schreef Roelof Wobben:
>>>
>>> As far as I understand recur is going back to the loop so number is
>>> never going back to 0
>>> but I see the problem (-(count coll)2 is changing it value and that
>>> schould not happen.
>>> So I think I have to set the initial value of counter in the let.
>>>
>>> what schould happen is this
>>>
>>> coll number counter
>>> 1) [1,2,3.4.5) 0 3
>>> 2) [2.3,4,5] 1 3
>>> 3) [3,4,5] 2 3
>>> 4) [ 4,5] 3 3
>>>
>>> so the (first coll) is executed which is 4.
>>>
>>> Am I at the right track now.
>>>
>>>
>>>
>>> Roelof
>>>
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