I once set out to make a ticket for it, but ended up not probably because 
it was going to take too much effort to describe or something. I was 
probably busy.

On Saturday, October 24, 2015 at 7:01:05 PM UTC-5, Gary Fredericks wrote:
>
> I've always thought this is bad behavior, since it's blatantly doing the 
> opposite of what the name advertises. I think either the boxed versions 
> should return the same result as the unboxed version, or (if the whole 
> point is to give good performance and so we don't want want users to be 
> able to accidentally use the unboxed versions) it should throw at 
> compile-time for boxed args.
>
> On Saturday, October 24, 2015 at 9:35:46 AM UTC-5, Andy Fingerhut wrote:
>>
>> I can't answer whether Clojure should do that.
>>
>> It is doing it because unchecked-multiply falls back to normal multiply, 
>> i.e. *, unless both of its arguments are primitive long values.  Even boxed 
>> Long values cause it to fall back to the behavior of *.  The same goes for 
>> unchecked-add and unchecked-subtract.
>>
>>
>> user=> (unchecked-multiply 2432902008176640000 21)
>> -4249290049419214848
>> user=> (unchecked-multiply 2432902008176640000 (Long. 21))
>>
>> ArithmeticException integer overflow 
>>  clojure.lang.Numbers.throwIntOverflow (Numbers.java:1501)
>>
>> Andy
>>
>>
>> On Fri, Oct 23, 2015 at 1:54 PM, Garrett Rowe <gmrow...@gmail.com> wrote:
>>
>>> Should `unchecked-multiply` throw an exception in this case? (see also: 
>>> http://stackoverflow.com/questions/33306984/why-does-my-hash-function-fail-with-arithmeticexception-integer-overflow-even/33308956#33308956
>>> )
>>>
>>> user> (reduce unchecked-multiply (range 1 22))
>>> ArithmeticException integer overflow  clojure.lang.Numbers.throwIntOverflow 
>>> (Numbers.java:1388)
>>>
>>> The loop-recur version also fails, unless you use a type hint:
>>>
>>> user> (loop [n 1
>>>              r (range 1 22)]
>>>         (if-let [a (first r)]
>>>           (recur (unchecked-multiply n a) (next r))
>>>           n))
>>> ArithmeticException integer overflow  clojure.lang.Numbers.throwIntOverflow 
>>> (Numbers.java:1388)
>>>
>>> user> (loop [n 1
>>>              r (range 1 22)]
>>>         (if-let [^long a (first r)]
>>>           (recur (unchecked-multiply n a) (next r))
>>>           n))
>>> -4249290049419214848
>>>
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>>
>>

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