I recognize 1+ isn't a valid input range, I was just surprised that pick didn't support the same notation with substring as without. In my actual code the matching "constant" is a word of variable length coming from another source. Yes, I could reorder to put the input word of interest first and use the "1+" notation; or there are several approaches, this just seemed the simplest had it worked.
-- Mike Harding z/VM System Support /sp CMSTSO Pipelines Discussion List <CMS-PIPELINES@vm.marist.edu> wrote on 12/28/2012 09:59:31 AM: > From: "John P. Hartmann" <jphartm...@gmail.com> > To: CMS-PIPELINES@vm.marist.edu, > Date: 12/28/2012 10:00 AM > Subject: Re: Pick input range inconsistency > Sent by: CMSTSO Pipelines Discussion List <CMS-PIPELINES@vm.marist.edu> > > 1+ is not an inputRange; hence substr is not a substring, but the > string ub delimited by s. Try 1.3 instead. > > On 28 December 2012 18:36, Michael Harding <mhard...@us.ibm.com> wrote: > > pipe literal abcdef 123456|pick 1+ == /abc/|cons > > abcdef 123456 > > Ready; T=0.01/0.01 09:29:34 > > pipe literal abcdef 123456|pick 8+ == /123/|cons > > abcdef 123456 > > Ready; T=0.01/0.01 09:29:57 > > pipe literal abcdef 123456|pick 8+ == /1234/|cons > > abcdef 123456 > > Ready; T=0.01/0.01 09:30:25 > > pipe literal abcdef 123456|pick 8+ == /1235/|cons > > Ready; T=0.01/0.01 09:30:31 > > pipe literal abcdef 123456|pick substr 1.3 of w2 == /123/|cons > > abcdef 123456 > > Ready; T=0.01/0.01 09:31:08 > > pipe literal abcdef 123456|pick substr 1+ of w2 == /123/|cons > > PIPPIC687E Relational operator expected; found tr. > > PIPMSG003I ... Issued from stage 2 of pipeline 1. > > PIPMSG001I ... Running "pick substr 1+ of w2 == /123/". > > Ready(00687); T=0.01/0.01 09:31:27 > > pipe query version > > PIPINX086I CMS/TSO Pipelines, 5654-030/5655-A17 1.0112 > > (Version.Release/Mod) - Generated 24 Jul 2012 at 06:07:28. > > Ready; T=0.01/0.01 09:32:19 > > > > Oops! > > -- > > Mike Harding > > z/VM System Support > > > > /sp >
