Why do you say that? I haven't noticed any documented requirement that
ties the implementation details of -hash and -isEqual together.
- Bryan
Sent from my iPhone
On Aug 20, 2009, at 4:27 PM, Clark Cox <clarkc...@gmail.com> wrote:
On Thu, Aug 20, 2009 at 12:33 PM, David
Duncan<david.dun...@apple.com> wrote:
On Aug 20, 2009, at 12:00 PM, Seth Willits wrote:
Returning 0 is certainly simpler :p
It is, but you can generally do better than just returning 0,
usually by
just extracting some bits from 'self', ala
-(NSUInteger)hash
{
uintptr_t hash = (uintptr_t)self;
return (hash >> 4);
}
This satisfies the condition of hash (two equal objects will have
the same
hash code)
No it doesn't. Writing the hash method like that basically prevents
you from having an isEqual that does anything other than a pointer
comparison.
--
Clark S. Cox III
clarkc...@gmail.com
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