On Thu, May 26, 2011 at 9:30 PM, Graham Cox <graham....@bigpond.com> wrote:
>
> I should mention this is in a 64-bit build, so doesn't that mean that 
> 'unsigned' is 64 bits?

No. 'unsigned' is the same size on both 32- and 64-bit The only
built-in types that are different between 32- and 64-bits are:

signed long
long (which is really the same as "signed long")
unsigned long
and any pointer type

All other built-in types remain the same size between the two.

-- 
Clark S. Cox III
clarkc...@gmail.com
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