When I define NS_BUILD_32_LIKE_64=1 I can simply write:
NSUInteger u = 12;
NSLog(@"u = %lu", u );
Otherwise I would need to use a cast like:
NSLog(@"u = %lu", (unsigned long)u );
or even more clumsy:
#if __LP64__
NSLog(@"u = %lu", u );
#else
NSLog(@"u = %u", u );
#endif
The 64-Bit Transition Guide for Cocoa just says:
"The NS_BUILD_32_LIKE_64 macro is useful when binary compatibility is not a
concern, such as when building an application."
So: why is this NS_BUILD_32_LIKE_64 not always defined (as default) and what
binary compatibility issues I have to be aware of?
Kind regards,
Gerriet.
_______________________________________________
Cocoa-dev mailing list (Cocoa-dev@lists.apple.com)
Please do not post admin requests or moderator comments to the list.
Contact the moderators at cocoa-dev-admins(at)lists.apple.com
Help/Unsubscribe/Update your Subscription:
http://lists.apple.com/mailman/options/cocoa-dev/archive%40mail-archive.com
This email sent to arch...@mail-archive.com
