Okay, now if I want to insert 1024 bytes of new data at the beginning of a
populated NSMutableArray, is there a better way than this:
NSMutableData *bigMData = ... // (approx 1MB of data);
int origlength = bigMData.length;
uint8_t *newBytesPtr = ...
. . .
// Shift contents over by 1024 bytes
[bigMData replaceBytesInRange:NSMakeRange(1024,origlength)
withBytes:bigMData.bytes
length:origlength];
// Add new contents to the beginning
[bigMData replaceBytesInRange:NSMakeRange(0,1024);
withBytes:newBytesPtr
length:1024];
This seems a bit messy.
-Carl
On Jul 12, 2014, at 1:51 PM, Matt Gough <devlists...@gmail.com> wrote:
> don’t you just want:
>
> [bigData replaceBytesInRange:NSMakeRange(0, 1024) withBytes:NULL length:0];
>
> ??
>
> I am sure NSMutableData is well optimized for shunting its contents around
> internally.
>
> Matt
>
>
> On 12 Jul 2014, at 20:36, Carl Hoefs <newsli...@autonomy.caltech.edu> wrote:
>
>> Basically what I would like is an NSMutableData method like this:
>>
>> - (void)resetDataRangeTo:(NSRange)range
>>
>> Parameters
>> range
>> The range within the contents of the receiver to be considered the new
>> contents.
>>
>>
>> But, since that doesn't exist yet, is it safe to "shift" the contents in
>> place of an NSMutableData? I'm trying to avoid having to copy the contents,
>> which is > 1MB.
>>
>> In this example, I want to remove the leading 1024 bytes in a large
>> NSMutableData:
>>
>> NSMutableData *bigData = ... // (approx 1MB of data);
>>
>> UInt64 byte_shift = 1024; // skip over first 1024 bytes
>> UInt64 new_length = bigMutData.length-byte_shift;
>> NSRange moveRange = NSMakeRange(0,new_length);
>>
>> [bigMutData replaceBytesInRange:moveRange
>> withBytes:bigMutData.bytes+1024
>> length:new_length];
>> [bigMutData setLength:new_length];
>>
>> -Carl
>>
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