On 11 Aug 2014, at 22:15, koko <k...@highrolls.net> wrote:

> In computing, the modulo (sometimes called modulus) operation finds the 
> remainder of division of one number by another.
> Given two positive numbers, a (the dividend) and n (the divisor), a modulo n 
> (abbreviated as a mod n) is the remainder of theEuclidean division of a by n. 
> For instance, the expression "5 mod 2" would evaluate to 1 because 5 divided 
> by 2 leaves aquotient of 2 and a remainder of 1, while "9 mod 3" would 
> evaluate to 0 because the division of 9 by 3 has a quotient of 3 and leaves a 
> remainder of 0; there is nothing to subtract from 9 after multiplying 3 times 
> 3. (Note that doing the division with a calculator won't show the result 
> referred to here by this operation; the quotient will be expressed as a 
> decimal fraction.)
> Although typically performed with a and n both being integers, many computing 
> systems allow other types of numeric operands. The range of numbers for an 
> integer modulo of n is 0 to n − 1. (n mod 1 is always 0; n mod 0 is 
> undefined, possibly resulting in a "Division by zero" error in computer 
> programming languages) See modular arithmetic for an older and related 
> convention applied in number theory.
> When either a or n is negative, the naive definition breaks down and 
> programming languages differ in how these values are defined.


Well put! In my mind, the logical thing to do is to return the reverse sequence 
as per mod function I copied. This makes more sense when using Cocoa because it 
means you can easily treat NSArray’s as circular lists without having to worry 
about edge conditions.

Cheers
Dave


_______________________________________________

Cocoa-dev mailing list (Cocoa-dev@lists.apple.com)

Please do not post admin requests or moderator comments to the list.
Contact the moderators at cocoa-dev-admins(at)lists.apple.com

Help/Unsubscribe/Update your Subscription:
https://lists.apple.com/mailman/options/cocoa-dev/archive%40mail-archive.com

This email sent to arch...@mail-archive.com

Reply via email to