Hello,
this a bit OT... And the message from the compiler is quite explicit
In java, you must declare all exception in the prototype of the function; in
this case,
you should enclose your code in a try/catch bloc
> -----Message d'origine-----
> Hello,
>
> i have following Problem with xsp:logic and getBytes
>
> my code is:
> --
> <?xml version="1.0" encoding="UTF-8"?>
> <xsp:page language="java"
> xmlns:xsp="http://apache.org/xsp";
> xmlns:xsp-request="http://apache.org/xsp/request/2.0";>
>
> <page>
> <xsp:logic>
> String saveAs = request.getParameter("saveAs");
> String name_enc = new String(saveAs.getBytes("8859_1"));
> System.out.println (name_enc);
>
> </xsp:logic>
>
> <wert><xsp-request:get-parameter name="saveAs" />
> </wert>
> </page>
>
> </xsp:page>
> --
>
> when i enter an encoding String in getBytes(....), i will get
> following
> error with cocoon:
> Exception java.io.UnsupportedEncodingException must be
> caught, or it must be
> declared in the throws clause of this method.
>
> how can i get the german characters, because the characters, which are
> printed with System.out.println, are not the same i entered
> as parameter.
>
>
> Georg Schmitt
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