<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:i18n="http://apache.org/cocoon/i18n/2.0";>
<xsl:template match="gender">
<i18n:text><xsl:value-of select="@sex"/></i18n:text>
<xsl:text/> <xsl:value-of select="name"/>
</xsl:template>
</xsl:stylesheet>
in catalogue_en.xml:
<message key="Male">Mr.</message>
<message key="Female">Mrs.</message>
in catalogue_de.xml:
<message key="Male">Frau</message>
<message key="Female">Herr</message>
Regards,
Joerg
kavitha ramesh wrote:
> Hi,
>
> I have an xml file which is as follows:
>
> simple.xml
> ----------
> <menu>
> <person>
> <gender sex="Male">
> <name>Ramesh</name>
> </gender>
> </person>
> <person>
> <gender sex="Female">
> <name>Kavitha</name>
> </gender>
> </person>
> <person>
> </menu>
>
> and my xsl file is as follows:
>
> simple.xsl
> ----------
>
> <i18n:text>text1</i18n:text>
> <i18n:text>text2</i18n:text>
>
>
> and my messages for i18n are as follows:
>
> messages_en
> -----------
> <message key="text1">Mr</message>
> <message key="text2">Mrs</message>
>
> messages_de
> -----------
> <message key="text1">Herrn</message>
> <message key="text2">Frau</message>
>
> If the sex is male, the browser should display
>
> Mr.Ramesh(English)
> Herrn.Ramesh(German)
>
> If the sex is female then the browser should display
>
> Mrs.Kavitha(English)
> Frau.Kavitha(German)
>
> How do I do this?Please help me,,,
>
> Kavitha.
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