kazdy commented on PR #7640: URL: https://github.com/apache/hudi/pull/7640#issuecomment-1385496680
Thanks for the explanation, so it seems like key generator must be deterministic and there's no way around it. What I do with hudi datasets where I need a surrogate key is that I just generate a column with UUID using [built-in spark uuid() function](https://spark.apache.org/docs/3.3.1/api/sql/#uuid). I think it's a valid way to do it :) I guess using engine-specific uuid() function in keygen would not change anything. -- This is an automated message from the Apache Git Service. To respond to the message, please log on to GitHub and use the URL above to go to the specific comment. To unsubscribe, e-mail: commits-unsubscr...@hudi.apache.org For queries about this service, please contact Infrastructure at: us...@infra.apache.org
