dear Ingo, >>> ... (1 + delta)^(m*n). >> >> This is true, and a delta > 2 follows from a Theorem in an >> upcoming paper by Matthieu Walraet and myself. > > Do you mean (1+delta) > 2, or really (1+delta) > 3?
Oops; I mean delta >= 1, so the base of the exponent is at least 2. (1+delta) is necessarily bounded by the base of liberties of 2.975734192... > Please let us know when a preprint is available on ArXiv or some other place. The original write-up by Matthieu is available at http://matthieuw.github.io/go-games-number/GoGamesNumber.pdf Our CG2016 submission both simplifies and improves on that, but that write-up should already convince you of how to achieve delta 1. regards, -John _______________________________________________ Computer-go mailing list Computer-go@computer-go.org http://computer-go.org/mailman/listinfo/computer-go
