On 23/10/2013 15:37, Paul Sandoz wrote:
:


Testing wise if you really want to use lambda expressions then they need to be 
explicitly marked as serializable otherwise it's gonna barf (as you probably 
found out):

         DoubleBinaryOperator plus = (DoubleBinaryOperator&  Serializable) (x, y) 
->  x + y;
Yes, that is what I was looking for (and meant to search the lambda serialization tests to see how to do this).


Should you test accumulation/addition/reset after deserialization just to make 
sure the value/identity are assigned correctly?

Good idea, I'll add that.

-Alan.

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