If you don't add any member fields, then no, I don't think you need to
change anything.
- Aaron
On Wed, Jun 3, 2009 at 4:11 PM, dealmaker <vin...@gmail.com> wrote:
>
> I have the following as my type of my "value" object. Do I need to
> implement
> readfields and write functions?
>
> private static class StringArrayWritable extends ArrayWritable {
> private StringArrayWritable (String [] aSString) {
> super (aSString);
> }
> }
>
>
> Aaron Kimball-3 wrote:
> >
> > If you can use an existing serializeable type to hold that field (e.g.,
> if
> > it's an integer, then use IntWritable) then you can just get away with
> > that.
> > If you are specifying your own class for a key or value class, then yes,
> > the
> > class must implement readFields() and write().
> >
> > There's no concept of introspection or other "magic" to determine how to
> > serialize types by decomposing them into more primitive types - you must
> > manually insert the logic for this in every class you use.
> >
> > - Aaron
> >
> > On Wed, Jun 3, 2009 at 2:41 PM, dealmaker <vin...@gmail.com> wrote:
> >
> >>
> >> Hi,
> >> I have only one field for the record. I wonder if I even need to
> define
> >> a
> >> member variable in class Record. Do I even need to implement readfields
> >> and
> >> write functions if I have only one field? Can I just use the "value"
> >> object
> >> directly instead of a member variable of value object?
> >> Thanks.
> >> --
> >> View this message in context:
> >>
> http://www.nabble.com/Do-I-need-to-implement-Readfields-and-Write-Functions-If-I-have-Only-One-Field--tp23860009p23860009.html
> >> Sent from the Hadoop core-user mailing list archive at Nabble.com.
> >>
> >>
> >
> >
>
> --
> View this message in context:
> http://www.nabble.com/Do-I-need-to-implement-Readfields-and-Write-Functions-If-I-have-Only-One-Field--tp23860009p23861181.html
> Sent from the Hadoop core-user mailing list archive at Nabble.com.
>
>
