On 12/19/14 5:34 AM, Stefan Seefeld wrote:
But if I declare the function f in reversed order:BOOST_PYTHON_MODULE(test) { def("f", f_double); def("f", f_int); } I will see "invoked f(int n = 5)" when I call f(5) and "invoked f(double d = 3.14)" when I call f(3.14) as it has to be. Why does it happen? Why does it depend on declaration order?It definitely shouldn't. If it does, please submit a bug report including the test, as well as details as to what compiler and OS you were observing the error on.
It's not a bug, it's as designed. Boost.python tries function overloads in reverse registration order and picks the first one that works, in the sense that all the arguments convert.
Alex _______________________________________________ Cplusplus-sig mailing list Cplusplus-sig@python.org https://mail.python.org/mailman/listinfo/cplusplus-sig
