On average, you'll find one N-bit collision after looking at O(2^(N/2)) random N-bit strings; how long does it take, on average, to find k collisions? O(k*2^(N/2))? -- Mike Stay Programmer / Crypto guy AccessData Corp. mailto:[EMAIL PROTECTED]
- Re: rate of finding collisions staym
- Re: rate of finding collisions Matt Crawford
- Re: rate of finding collisions staym
- Re: rate of finding collisions Ian Goldberg
- Re: rate of finding collisions Paul Crowley
- Re: rate of finding collisions David Wagner