On 01/02/2012 13:32, William Whyte wrote : > You can obviously prove it in the case where Alice claims she knows > SHA-1(SHA-1(m)), which seems to be the same claim. Alice discloses h and claims knowledge of m with h=SHA1(m).
That's not equivalent to claiming knowledge of SHA-1(SHA-1(m)), which anyone can compute as SHA-1(h). Francois Grieu _______________________________________________ cryptography mailing list cryptography@randombit.net http://lists.randombit.net/mailman/listinfo/cryptography
