> I'm having a problem working with 2 linked lists in
> problem 3. I create 2 objects of the class "DLList,"
> call them list1 and list2, and, from looking at the
> debugger, no problem with that. The class DLList
> includes a "print()" function that prints the list.
> If, after creating list1 and list2 I use this
> function, however, the 2 lists are printed out
> identical. It's like the program can't distinguish
> between the 2 lists after they are created, even
> though the memory address is different... does anybody
> have any idea why this could be happening? I'm really
> quite cluseless... :(
>
> Thank you, enjoy the beautiful weekend!
>
> --Alessandro
>
> PS: Here's the code I'm looking at:
>
> int [] array ={1,3,3,4};
> list1=new DLList (array);
>
> int [] array2 = {3,4,5,6};
> list2= new DLList (array2);
>
> list1.print();
> list2.print();
> OUTPUT:
> {3,4,5,6}
> {3,4,5,6}
My guess is that your DLList has this kind of form:
public class DLList {
private int[] my_array;
public DLList(int[] array)
{
my_array = array;
}
// other code ...
}
The difficulty here is to understand clearly what "my_array = array;" means.
If my guess is right, then what you are doing is letting my_array point to array (so
my_array just
becomes another name for the original array). What you should do here is allocate
memory for
my_array and then make a real copy of array into my_array (copying all the elements).
Hans
