Dave Rolsky wrote:
On Thu, 13 May 2004, Danny Rathjens wrote:
Am I misunderstanding these methods or is this a bug? ;)
You're misunderstanding, but it may be a doc problem.
perl -MData::Dumper -MDateTime -wle'$past = DateTime->now->subtract(months=>2); $now =
DateTime->now; $dur = $now->delta_days($past); print Dumper $dur; print $dur->days'
$VAR1 = bless( {
'seconds' => 0,
'minutes' => 0,
'end_of_month' => 'wrap',
'nanoseconds' => 0,
'days' => 61,
'months' => 0,
'sign' => 1
}, 'DateTime::Duration' );
5
If you asked for $dur->weeks you'd get 8 weeks. 8 weeks + 5 days equals
61 days total.
If you asked for $dur->delta_days or $dur->in_units('days') you'd get 61.
perl -MData::Dumper -MDateTime -wle'$past = DateTime->now->subtract(months=>2); $now =
DateTime->now; $dur = $now - $past; print Dumper $dur; print $dur->delta_days'
$VAR1 = bless( {
'seconds' => 0,
'minutes' => 0,
'end_of_month' => 'wrap',
'nanoseconds' => 0,
'days' => 0,
'months' => 2,
'sign' => 1
}, 'DateTime::Duration' );
0
This I think is pretty straightforward. There is no way to convert months
to days or vice versa.
ok, I was confused into thinking this was possible by my $dur = $now->delta_days($past)
in my first example, which results in 61 days due to a two month difference.
I realize now that DT::delta_days means something different than
DT::Duration::delta_days
since DT::delta_days knows whether it is a leap year but a DT::Duration object doesn't.
Perhaps if you could anchor one end of the duration you would be able to convert all of
the components of a duration into a single unit; ah I guess that is what DT::Span is
for.
Or just using epochs, :)
I've added something to the docs which will hopefully clarify this. In
general, I'd recommend people consider using DateTime::Format::Duration,
since it's much easier to get exactly what you want using that module.
Thanks very much for your hard work on these great modules.
--
_.,-*~`^'~*-,._ Danny Rathjens _.,-*~`^'~*-,._
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