Zefram wrote: >[EMAIL PROTECTED] wrote: > >How do I compute the number of hours in a day in a specific time zone? > > Try this:
Thanks for the working example. It's helpful. > It ought to be possible to do the interval calculation using > DateTime::Duration instead of ->epoch, but the behaviour of DT::D is > unreasonably confusing and I couldn't get it to work. (Strangely, I got > a version that worked fine for America/New_York, where all the days are > integer numbers of hours, but lost the fractional hour of 2007-12-09 in > America/Caracas, which was 24.5 hours long.) > > Beware that the above code assumes that > midnight exists every day. We recently had a thread > <http://www.nntp.perl.org/group/perl.datetime/2008/10/msg7086.html> about > midnight not existing in some timezones, specifically America/Sao_Paulo. It's funny you should mention that thread. It's what inspired my little exercise, which I thought was going to be easier than it is. Here's what I *really* want to do: I want to iterate the time zones of the world to generate a report of all days that aren't exactly 24 hours. I want to handle America/Caracas and America/Sao_Paulo correctly. You mentioned 2007-12-09 was 24.5 hours long in Venezuela. This is precisely the kind of outliers I'm after. So I'm looking for the best, most canonical, most true-to-the-spirit-of-DateTime way to accomplish this using, presumably, DateTime::Duration and possibly DateTime::Format::Duration. Jim Monty
