> The equation whose solution describes the new shape function varies on each
> cell and is determined by the original shape function on that cell.for this
> matter,creating a triangulation object of the reference cell might not help
> and I'm also not quite familiar with how the mapping works. Since I can get
> all the information create_triangulation() function needs through a
> cell_iterator, I suppose I can create a triangulation object of the real
> cell this way?

Yes, certainly.
W.

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Wolfgang Bangerth                email:            [email protected]
                                 www: http://www.math.tamu.edu/~bangerth/

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